Deep beam (strut-and-tie)

Checks a deep beam by the strut-and-tie method of ACI 318-19 Chapter 23 with 9.9. Strength design, φ = 0.75. Two ready models: one point load, which is a transfer girder under a column and, seen upside down, a two-pile cap; and two symmetric point loads. You choose the model's node depths and the checks tell you if they work.

Inputs of the deep beam

  • Beam: b, h, the span between support centers, the load's distance, and the length past each support.
  • Bearings: the length at the supports and under the loads, along the span.
  • Top node depth ws and tie node depth wt: the model's geometry. The lever arm is h − ws/2 − wt/2. Try wt as the depth the bars take, and ws as what the top strut needs: it is yours to iterate.
  • βc: Table 23.4.3(b): at a bearing up to the lesser of √(A2/A1) and 2. 1.0 is on the safe side.
  • Depth d: for Eq. 9.9.2.1 and the grid's spacing. 0 takes h − wt/2.
  • Loads: unfactored, at each point. Own weight is added as dead load at the points if you choose: a lumping that is your decision.
  • Tie: bars, anchorage, cover. A headed or mechanical anchorage is your own check, reported as such.
  • Distributed steel: bars on each face, both ways. If it meets Table 23.5.1, interior struts take βs = 0.75; if it falls short, βs = 0.4, unless you say the strut is laterally restrained (23.5.3) or you choose Eq. 23.4.4. 9.9.3.1 requires the grid anyway, so a shortfall still fails.

Auto-design varies the tie bars and the distributed grid. The beam, the bearings, the node depths and the loads stay yours.

Checks performed

CheckBasis
Truss forcesSolved by the library's stiffness method; statics in hand checks
Angle23.2.7: at least 25 degrees
Section limitEq. 9.9.2.1: Vu ≤ φ 10√f'c b d. Eq. 23.4.4 if you use it for βs
Diagonal struts23.4: fce = 0.85 βc βs f'c, at the narrower end; width lb sin θ + wt cos θ at a support, bearing sin θ + ws cos θ at a load
Top strut (two loads)23.4: βs = 1.0
Nodes23.9: βn = 0.80 at the supports (one tie), 1.0 under the load; the bearing, tie and strut faces
TieEq. 23.7.2: Ats ≥ T / (φ fy); 9.9.3.2 minimum
Tie anchorage23.8.3: straight or hooked, past the extended nodal zone
Distributed steel9.9.3.1: 0.0025 each way; 9.9.4.3: spacing at most d/5 and 12 in.

Limitations

  • Two ready models and no truss of your own. Not offered: three-dimensional pile caps, corbels by strut-and-tie, openings, uniform loads as multiple panels, prestress, seismic 23.11.
  • Strut widths use the bearing and node depth as drawn; a node with unequal stress faces is not reshaped.
  • Unequal two-point loads have no direct truss here. Model them with Truss analysis and check the pieces by hand.
  • The tie's centroid is taken at wt/2: fit the bars inside the depth yourself (23.8.1).
  • λ enters only in Eq. 23.4.4, as in the code. Chapter 23 has no λ in fce.

Verification examples

Verification status: 46 values compared in 7 examples (4 published, 3 hand calculations from the cited equations): 42 within tolerance, 4 recorded deviations. Code basis: the provisions it uses were read in the target edition.

ExampleSourceValues
Two point loadsACI SP-17(14), Strut-and-Tie Example 1, pp. 660 to 667 (318-14)Pu 456, S1 and T1 533 kips; Ast 11.8 in²; φ fce 2,550, 1,913, 2,040 psi; φ Fns 673 and 918; φ Fnn 734 kips
One point loadStructurePoint DE-STM, pp. 10 to 16 (318-14)Pu 638.5, R 319, strut 603, tie 512 kips; angle 32 degrees; φ 10√f'c b d 512 kips; Ast 11.4 in²

Three published values differ on purpose. SP-17(14) prints the limit on Vu with 0.85, an older factor; the code has 0.75. A strut without distributed steel is 0.6 in 318-14 and 0.4 in 318-19. StructurePoint's extended zone follows its own node depth from a stress; here the depth is what you enter. Hand checks: a load off center, βc, Eq. 23.4.4. Both examples are to ACI 318-14. ACI MNL-17(21) Chapter 14 comes after wave 7 and would confirm these to 318-19; SP-17(14) Examples 2 to 5 and the FHWA and TxDOT worked examples are not run.